Hello Ahmed,
Thank you so much for the confirmation.
Onil
- Ahmed Vawda <avawda@aksugar.co.ae> wrote:
> Hi Onil,
>
> Yes, your equations are correct. The velocity will
> be the average velocity
> over the cross-sectional area, as confirmed by other
> forum members.
> However, I cant recall coming across steam
> velocities reported in m/hr.
> They are usually reported in m/sec or ft/sec.
> For example for superheated steam, I design on 40 -
> 75 m/s.
> If you use m/hr it would be 144,000 m/hr - 270,000
> m/hr.
> Both are the same, but the m/sec is generally the
> dimension I have see in
> the literature since my university days.
>
> Ahmed Vawda
> Process Engineer
> Al Khaleej Sugar - Dubai
>
> -----Original Message-----
> From: nilo aninon [mailto:onil8001@yahoo.com]
> Sent: Wednesday, September 19, 2001 5:42 PM
> To: <a href="/group/PipingDesign/post?postID=lpIwu5WhSKTLpYXmEWQ5CgQUgzjdeDQxwlRIeG1Uwu5lUoKSMVGY1CKnCMrbt5HgMwGIS73GJYbPqrcBhwHRaKXrBYSY">pipingdesign@yahoogroups.com</a>
> Subject: [PipingDesign] STEAM VELOCITY
>
>
> Hi everybody,
>
> To anybody who is very much knowlegeable about this
> subject matter, please share a piece of your
> knowledge.
>
> Is Q=A*V formula can be used in solving theoritical
> steam velocity? Say, I have already known the mass
> flow of steam in kg/hr. Then through the steam
> tables
> I can extract value for specific volume of steam in
> m3/kg. With the two data known, I think I can
> already
> solved for the velocity of steam using the above
> mentioned relation V=Q/A, where:
>
> Q=volumetric flow, m3/hr
> A=cross sectional area of pipe, m2
>
> Substituting the value,
> Q=mass flow of steam (kg/hr)*specific volume (m3/kg)
> Q=m3/hr
>
> Therefore,
> V=Q(m3/hr)/A(m2)
> V=m/hr
>
> I was quite confused because the result of my
> calculation is very far or too high compared with
> the
> data provided by some boiler accessories
> manufacturer.
>
> Hope to hear from the experts.
>
> Very truly yours,
>
> Onil
>
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Received on Fri Sep 28 09:38:00 2001