H Onil
I did reply to your query (below)and it agrees generally with our other colleagues sentiments. It did not appear on the list for some reason. If you or any one else for that matter, would like a spreadsheet which calculates velocity with three inputs, pipe diameter, steam pressure and steam mass flow, please e-mail me directly.
Ahmed Vawda
Al Khaleej Sugar - Dubai
-----Original Message-----
From: Ahmed Vawda [mailto:avawda@aksugar.co.ae]
Sent: Thursday, September 20, 2001 9:19 AM
To: 'PipingDesign@yahoogroups.com'
Subject: RE: [PipingDesign] STEAM VELOCITY
Hi Onil,
Yes, your equations are correct. The velocity will be the average velocity over the cross-sectional area, as confirmed by other forum members. However, I cant recall coming across steam velocities reported in m/hr. They are usually reported in m/sec or ft/sec. For example for superheated steam, I design on 40 - 75 m/s. If you use m/hr it would be 144,000 m/hr - 270,000 m/hr. Both are the same, but the m/sec is generally the dimension I have see in the literature since my university days.
Ahmed Vawda
Process Engineer
Al Khaleej Sugar - Dubai
-----Original Message-----
From: nilo aninon [mailto:onil8001@yahoo.com]
Sent: Wednesday, September 19, 2001 5:42 PM
To: <a href="/group/PipingDesign/post?postID=P1lkZY95WpghQ1jRS2yzqqNcCxp-hkjvPRpvDYqM7dSWByS9cGHrkM3u83LFojpS5Mn7_nLUTMtijmpRMqMXBj8r">pipingdesign@yahoogroups.com</a>
Subject: [PipingDesign] STEAM VELOCITY
Hi everybody,
To anybody who is very much knowlegeable about this subject matter, please share a piece of your knowledge.
Is Q=A*V formula can be used in solving theoritical steam velocity? Say, I have already known the mass flow of steam in kg/hr. Then through the steam tables I can extract value for specific volume of steam in m3/kg. With the two data known, I think I can already solved for the velocity of steam using the above mentioned relation V=Q/A, where:
Q=volumetric flow, m3/hr
A=cross sectional area of pipe, m2
Substituting the value,
Q=mass flow of steam (kg/hr)*specific volume (m3/kg)
Q=m3/hr
Therefore,
V=Q(m3/hr)/A(m2)
V=m/hr
I was quite confused because the result of my calculation is very far or too high compared with the data provided by some boiler accessories manufacturer.
Hope to hear from the experts.
Very truly yours,
Onil
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Your use of Yahoo! Groups is subject to <a href="http://docs.yahoo.com/info/terms/">http://docs.yahoo.com/info/terms/</a> Received on Sat Sep 29 04:06:00 2001
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