Hi Ralph
>he factor in the mill tolerance in the equation for the min. req'd
>thicknes..
>if u let hmtr = 1-mill tolerance and c = mechl allowance +CA
>then tm = (t+c)/hmtr or (t+c)/0.875 for 12.5%
My understanding of the spreadshhet was that tR = (min thickness + corrosion)/0.875
The 0.875 could be a factor for mill tolerance, but the mill tolerance should be subtracted from the nominal wall, not added to the min thickness as it is a manufacturer's tolerance based on the nominal wall.
The mill tolerance is used correctly in the column TA = T * 0.875, so the tR column seemed to be redundant.
Regards
Barbara
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