Re: FW: Bending Thermoplastic Pipe

From: <Geoff>
Date: Sun Mar 09 2003 - 18:15:00 EST


Steve,

Thanks for that. My Alzheimer's was playing up there for a minute. I guess local buckling is the problem particularly if the pipe ovalises.

The pipe material inquestion is actually ABS which has a higher stiffness (modulus) than PE but will creep as you say.

Geoff
--- Steve McKenzie <Mechproj@xtra.co.nz> wrote:



Reactions.
I thought about this, and realised that once the pipe is formed, the entire reaction is taken by the two supports at each end because the bending moment along the curved pipe is constant.The intermediate supports carry no load once the curved pipe is in place. You will need intermediate supports to curve the pipe around, unless you use a tirfor or chainblock etc hooked onto the pipe ends. Assuming there is a straight extension at each end the reaction at each of the 4 end supports will be M/s; where M is as calculated below, and s is the distance between the end 2 blocks. You could use a single moment restraint at each end, but I think pipe crushing could become an issue. None of the above includes allowance for hydrostatic/dynamic loads which will have to be added separately.

Hope this helps.

Cheers

Steve McKenzie

-----Original Message-----
From: Steve McKenzie [mailto:Mechproj@xtra.co.nz] Sent: Friday, March 07, 2003 10:47 PM
To: <a href="/group/PipingDesign/post?postID=2-W2c2bmcPJfL2ipVLD0EWym5buFPdl3c6OlMYm6alqgeV_-StRRxa4dVtmMH0jgoD6UHEmPL7X8RZJEztps10SSbrw">PipingDesign@yahoogroups.com</a> Subject: RE: [PipingDesign] Bending Thermoplastic Pipe

Hi Geoff

If you are talking poly pipe at 20 Deg C you shouldnt have any problems if the SDR is 41 or less and the installation temperature is 20C or more. This is within standard limits as given by James Hardie Pipelines. For your question, consider the following approximation ignoring local effects:

To work out the stresses, draw the installation. You will have nine supports for the pipe spaced at 11.25 degrees. The intermediate seven supports will be inside the bend radius and the two at the ends will be outside the the radius pushing inwards.
For fibre stress in the pipe you may remember from school: M/I = sigma/y = E/R
This gives sigma = Ey/R where sigma is fibre stress, E is Youngs Modulus, y is the pipe radius, and R is the bend radius. This is an approximation as the standard formula assumes the deflection curve is circular. For the reaction forces I think we will have to assume that the bending moment is constant between the seven middle supports, and rises from zero to a maximum from the first to the second support and the same at the other end. We know M = sigma*I/y from above and we know the distance between the supports so we can calculate the end reactions. I havent thought about the reactions at the seven intermediate supports yet, but it seems unlikely that their outward reaction would exceed the inward reaction of the end supports. I would probably use vectors, but there is bound to be an easier way. Chris can probably provide a more precise answer.

However as you know if you leave the bent pipe in the sun for a while the stresses will drop drastically due to plastic deformation. I have "preformed" large sweeps this way using a Tirfor and the sun. Its just the reverse to unrolling a coil of poly in the sun to straighten it out.

Sorry I didnt get to Sydney to catch up with you; the bastards in Melbourne made me work both weekends.

Cheers

Steve McKenzie

-----Original Message-----
From: Geoff Stone DD&D Australia [mailto:blenrayaust@yahoo.co.uk] Sent: Friday, March 07, 2003 4:24 PM
To: paul bowers
Subject: [PipingDesign] Bending Thermoplastic Pipe

Question.

A client wants to bend a DN 225 plastic pipe in a 10 m radius. How do I find the stresses in the pipe wall arising from the bending process? What would be
the loads at supports spaced every 2000mm?

Geoff Stone



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