Re: [PipingDesign] store energy

On Aug 5, 2008, at 10:50 AM, Erik Scheir wrote:

>
> The internal energy of an ideal gas is a function of temperature
> only. This makes physical sense because there is an assumption in
> ideal gas behavior that there is no interaction between the
> molecules when we write \bgroup\color{blue}$ P \ensuremath{\overline
> {V}} = RT$\egroup
>
> Interal Energy: ÆU=3/2nRT

The stored energy in a gas container is actually the integral of the increments of external work, not internal energy. You make the Integral of PdV using the adiabatic relationship pressure x density^gamma = constant. The value of the integral between test pressure and atmospheric pressure is the released energy.

Christopher Wright P.E. |"They couldn't hit an elephant at chrisw@skypoint.com | this distance" (last words of Gen.

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